That means a point and its image are both same distance from the line of reflection. Distance from point to line of reflection must match distance from line of reflection to the final image point. If you instead have a figure and have to reflect across a given line, think about drawing lines from original figure's vertices perpendicular to the line of reflection. If the point and image are not on a horizontal or vertical line, you'd have to find the midpoint between them, calculate the slope of the line containing the three points (using slope formula), then find perpendicular line of reflection using negative reciprocal of the slope, and the slope-intercept format with midpoint as the known point. Then the line of reflection is the perpendicular bisector of the segment. Compilation of Free online math resources.If your browser is so outdated or unusual that the linked advice doesn't work, consider these ideas.You will need to install a UserScript loader first.You will see formatted as in a textbook if the MathJax UserScript is installed and working. Type this as an example (replace the [- with [ when typing): being a jerk (Jerks get banned.) Using LaTeX.image or video link-posts (Links to articles, Desmos, Wolfram|Alpha, and the like are fine.).one-sentence posts (Have some respect for people who take time to answer your question and follow the posting rules.).
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